#27 Remove Element

LeetCode

Given an array nums and a value val, 
remove all instances of that value in-place and return the new length.

Do not allocate extra space for another array, 
you must do this by modifying the input array in-place with O(1) extra memory.

The order of elements can be changed. 
It doesn't matter what you leave beyond the new length.
Example 1:

Given nums = [3,2,2,3], val = 3,

Your function should return length = 2, 
with the first two elements of nums being 2.

It doesn't matter what you leave beyond the returned length.

input: 給一串數字陣列，跟一個 val
output: 若數字陣列裡有包含 val 的都移掉，回傳長度

Example 1:

Given nums = [3,2,2,3], val = 3,

Your function should return length = 2, with the first two elements of nums being 2.

It doesn't matter what you leave beyond the returned length.
Example 2:

Given nums = [0,1,2,2,3,0,4,2], val = 2,

Your function should return length = 5, with the first five elements of nums containing 0, 1, 3, 0, and 4.

Note that the order of those five elements can be arbitrary.

It doesn't matter what values are set beyond the returned length.
Clarification:

Confused why the returned value is an integer but your answer is an array?

Note that the input array is passed in by reference, which means modification to the input array will be known to the caller as well.

Internally you can think of this:

// nums is passed in by reference. (i.e., without making a copy)
int len = removeElement(nums, val);

// any modification to nums in your function would be known by the caller.
// using the length returned by your function, it prints the first len elements.
for (int i = 0; i < len; i++) {
    print(nums[i]);
}

*/

/**
 * @param {number[]} nums
 * @param {number} val
 * @return {number}
 */
var removeElement = function(nums, val) {}

如何解

設 pointer，若 nums[pointer] == val, 那就把 array 裡的值移掉

var removeElement = function(nums, val) {
  let pointer = 0;
  while(pointer < nums.length){
      if(nums[pointer] == val){
          nums.splice(pointer, 1)
      }else{
          pointer ++;
      }
      
  }
  return nums.length;
 };